A galvanic cell consists of an Ag( s )|Ag + ( aq ) half-cell and a Cu( s )|Cu 2+

Question

A galvanic cell consists of an Ag(s)|Ag+(aq) half-cell and a Cu(s)|Cu2+(aq) half-cell connected by a salt bridge. Reduction occurs in the silver half-cell. The cell can be represented in standard notation as

A. Ag(s)|Ag+(aq)|Cu(s)|Cu2+(aq)

B. Cu(s)|Cu2+(aq)||Ag+(aq)|Ag(s)

C. Cu2+(aq)|Cu(s)||Ag(s)|Ag+(aq)

D. Ag+(aq)|Ag(s)||Cu(s)|Cu2+(aq)

E. Cu(s)|Cu2+(aq)||Ag(s)|Ag+(aq)

A. Ag(s)|Ag+(aq)|Cu(s)|Cu2+(aq)

B. Cu(s)|Cu2+(aq)||Ag+(aq)|Ag(s)

C. Cu2+(aq)|Cu(s)||Ag(s)|Ag+(aq)

D. Ag+(aq)|Ag(s)||Cu(s)|Cu2+(aq)

E. Cu(s)|Cu2+(aq)||Ag(s)|Ag+(aq)

Explanation / Answer

The cell notation includes

A salt bridge : //

Left hand side as anode on which oxidation will occur

and right hand side as cathode on which reduction will occur.

So redcution half cell : Ag+(aq)|Ag(s)

Oxidation half cell : Cu(s)|Cu2+(aq)

Oveall cell : Option B

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