Problem At 248 °C and a total pressure of 1.00 atm the degree of dissociation of

Question

Problem At 248 °C and a total pressure of 1.00 atm the degree of dissociation of SbCl ) is = 0.718 for the reaction SbCls(g) SbC13(g) + Cl2(g) The degree of dissociation is defined as number of moles of SbCl5 dissociated at equilibrium original number of moles of SbCl5 a= (a) What is the value of the equilibrium constant K(T) at 248 °C and 1.00 atm? (b) What is the value of K, at the same temperature when the pressure is 5.00 atm? Assume that under these conditions the system at equilibrium behaves as an ideal gas mixture. (c) what is the value of the degree of dissociation in the conditions of part (b)?

Explanation / Answer

Answer

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.