physical Problem 1 At 248 C and a total pressure of 1.00 atm the degree of disso

Question

physical Problem 1 At 248 C and a total pressure of 1.00 atm the degree of dissociation of SbCl(9) is 0.718 for the reaction The degree of dissociation a is defined as number of moles of SbCl dissociated at equilibriu original number of moles of SbC (a) What is the value of the equilibrium constant K (T) at 248 C and 1.00atm? (b) What is the value of K at the same temperature when the pressure is 5.00 atm? Assume that under these conditions the system at equilibrium behaves as an ideal gas mixture (c) What is the value of the degree of dissociation in the conditions of part (b)? Problen 2 Which one of the following statements isfare incorrect for the reaction at low pressure? Please notice that your answer will not count unless you explain and justify your choice(s). (e) If initially there was only NaHCO () present, then where is the standard chemical potential of species A. (e) ,G 0 in the system at the instant when only NaHC02(s) is present in the reaction vessel

Explanation / Answer

1) SbCl5(g)   <-------------> SbCl3(g) + Cl2(g)

a) Let initially, pressure of SbCl5 = 'x' atm ; Cl2 & SbCl3 = 0 atm

At equilibrium, pressure of SbCl5 = (x - 0.718x) atm ; Cl2 & SbCl3 = 0.718x atm

Now, total pressure at eqb., = 1 atm

Thus, x + 0.718x = 1

or, 1.718x = 1

or, x = 1.393 atm

Now, Equilibrium constant, K(T) = (PSbCl5)/{(PSbCl3)*(PCl2)} = (1.393-0.718*1.393)/(0.718*1.393)2 = 0.393

b) The value of the equilibrium constant depends only on temperature and enthalpy of the reaction.Thus, the value of K(T) remains the same when the pressure is 5 atm

c) Let the degree of dissociation be 'a'

Now, Let initially, pressure of SbCl5 = 'x' atm ; Cl2 & SbCl3 = 0 atm

At equilibrium, pressure of SbCl5 = (x - ax) atm ; Cl2 & SbCl3 = ax atm

Now, total pressure at eqb., = 5 atm

Thus, x + ax = 5

or, x = 5/(1+a)

Now, K(T) = (PSbCl5)/{(PSbCl3)*(PCl2)} = {(5-5a)/(1+a)}/{(5a)2/(1+a)2)}

or, 0.393 = 5(1+a)*(1-a)/25a2 = (1-a2)/5a2

or, 1.963a2 = 1- a2

or, a2 = 0.337

or, a = 0.581

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