1 Serum from a 50 yr old man was analyzed for both prostatic acid phosphatase(PA
ID: 87490 • Letter: 1
Question
1
Serum from a 50 yr old man was analyzed for both prostatic acid phosphatase(PAP) and prostate specific antigen(PSA) following a digital rectal examination of the prostate. The PAP result is 6.0 ug/L (URL= 3.0 ug/L) and the PSA is 2.0 ug/L (URL=4.0 ug/L). Both tests are repeated on the same sample and the results remain unchanged. What is the most likely explanation?
2
Which set of the following laboratory results is most likely from a patient who has suffered an acute MI? Reference intervals are in parenthesis.
Total CK (10-110 U/L)
CK-MB (1-6 ug/L)
CK-Index (1%-2.5%)
760 U/L
16 ug/L
170 U/L
14 ug/L
160 U/L
4 ug/L
D
80 U/L
2 ug/L
2.5%
2
Given the following information for a rate reaction, calculate the activity of a serum specimen for alanine aminotransferase in international units per liter (IU/L).
Time
Absorbance
1 min
1.104
Specimen volume= 20 uL
2 min
1.025
Reagent volume= 3.0 mL
3 min
0.950
Molar absorptivity for NADH at 340 nm= 6.22 x 103 L/mol cm
4 min
0.873
Light path= 1 cm
186
198
1857
1869
Total CK (10-110 U/L)
CK-MB (1-6 ug/L)
CK-Index (1%-2.5%)
A760 U/L
16 ug/L
2.1% B170 U/L
14 ug/L
8.2% C160 U/L
4 ug/L
2.5%D
80 U/L
2 ug/L
2.5%
Explanation / Answer
Answer:
1) Serum from a 50 yr old man was analyzed for both prostatic acid phosphatase(PAP) and prostate specific antigen(PSA) following a digital rectal examination of the prostate. The PAP result is 6.0 ug/L (URL= 3.0 ug/L) and the PSA is 2.0 ug/L (URL=4.0 ug/L). Both tests are repeated on the same sample and the results remain unchanged. What is the most likely explanation?
2) Which set of the following laboratory results is most likely from a patient who has suffered an acute MI? Reference intervals are in parenthesis.
The laobratory results corresponding to a person suffering from acute Myocardial Infarction is:
The set of the following laboratory results is most likely from a patient who has suffered an acute MI is (B)
3) Given the following information for a rate reaction, calculate the activity of a serum specimen for alanine aminotransferase in international units per liter (IU/L).
Based on the information given:
Total CK (10-110 U/L) CK-MB (1-6 ug/L) CK-Index (1%-2.5%) A 760 U/L 16 ug/L 2.10% B 170 U/L 14 ug/L 8.20% C 160 U/L 4 ug/L 2.50% D 80 U/L 2 ug/L 2.50%Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.