2 Hzoay Nanso say 4, H SO 2 NaOH a L5 sulfurous acid a strong or weak acid? b. W

Question

2 Hzoay Nanso say 4, H SO 2 NaOH a L5 sulfurous acid a strong or weak acid? b. What is the definition of a weak acid? c, write the ionic and net ionic equation for the reac only show separated ions for compounds that actually dissociate in water- see b, above) d If21.00 NaoH solution is used to titrate 28.75 ml of Hrso, aq) to the first ml of 0 0950 N And at the first eq pt how many H ions have reacted? e What total volume of NaOH solution would be needed to get to the second equivalence point? ml f Use your answer to part e to compute the normality of the Hasov

Explanation / Answer

H2SO3 + NaOH -------> 2H2O + Na2SO3

(a) Sulfurous acid is a weak acid because it doesn't dissociate completely into H+ and SO3^2- ions.

(b) A weak acid doesn't dissociate completely and releases only some amount of H+ ions in a solution

(c)

ionic reaction:

2H+(aq) + SO3^2-(aq) + 2Na+(aq) + 2OH-(aq) ---> 2Na+(aq) + SO3^2-(aq) + 2H2O(l)

net ionic reaction:

2H+(aq) + 2OH-(aq) ---> 2H2O(l)

(d)

At first equivalence pt.

moles of NaOH = moles of H2SO3

For NaOH Normality = molarity because equivalent mass = molar mass

Molarity * Volume of solution for NaOH = Molarity * Volume of Solution for H2SO3

0.095 M * 21 mL = M * 28.75 mL

M = 0.0694 M

(e) Volume of NaOH required to reach second equivalence point = 2 * Volume of NaOH for 1st equivalent point

= 2 * 21 mL = 42 mL

So, total volume = 21 + 42 = 63mL

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