HELP ME WITH THIS I AM SO STRUGGLING A chemical engineer is studying the followi
ID: 873369 • Letter: H
Question
HELP ME WITH THIS I AM SO STRUGGLING
A chemical engineer is studying the following reaction: At the temperature the engineer picks, the equilibrium constant Kp for this reaction is 3.6 . The engineer charges (fills) four reaction vessels with nitrogen monoxide and hydrogen, and lets the reaction begin. He then measures the composition of the mixture inside each vessel from time to time. His first set of measurements are shown in the table below. Predict the changes in the compositions the engineer should expect next time he measures the compositions.Explanation / Answer
For the given reaction
Kp = (pN2) (pH2O)2 / (pH2)2(pNO)2 = 3.6 = (xN2) (xH2O)2 / (xH2)2(xNO)2 X Total pressure
The value of Kp remains same if the temperature remains the same.
so case 1
Total pressure = 22.25
(pN2) = 3.38 / 22.25 = 0.152
(pH2O) = 3.59 / 22.25 = 0.161
(pH2) = 5.45 / 22.25 = 0.245
(pNO) = 9.83 / 22.25 = 0.442
Kp = 0.152 X 0.026 / 0.06 X 0.195 = 0.337 < original Kp so to maintain the equilibrium we need to decrease the concentration of reactants and increase concentration of products.
So change in concentration of the following species will be
(N2) = increase
(H2O) = increase
(H2) = decrease
(NO) =decrease
Case 2
Total pressure = 22.52
(pN2) = 3.92 / 22.52 = 0.174
(pH2O) = 4.13 / 22.52 = 0.183
(pH2) = 5.18/ 22.52 = 0.230
(pNO) = 9.29 / 22.52 = 0.412
Kp = 0.174 X 0.0334 / 0.053 X 0.169 = 0.648 < original Kp so to maintain the equilibrium we need to decrease the concentration of reactants and increase concentration of products.
So change in concentration of the following species will be
(N2) = increase
(H2O) = increase
(H2) = decrease
(NO) =decrease
Case 3
Total pressure = 21.75
(pN2) = 2.38 / 21.75 = 0.109
(pH2O) = 2.59 / 21.75= 0.119
(pH2) = 5.95 / 21.75 = 0.273
(pNO) = 10.83 / 21.75 = 0.497
Kp = 0.109 X 0.014 / 0.074 X 0.247 = 0.0.83 < original Kp so to maintain the equilibrium we need to decrease the concentration of reactants and increase concentration of products.
So change in concentration of the following species will be
(N2) = increase
(H2O) = increase
(H2) = decrease
(NO) =decrease
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.