Having trouble with this lab. This is the table. I am trying to figure out the f
ID: 871333 • Letter: H
Question
Having trouble with this lab. This is the table. I am trying to figure out the final reaction rate. Can someone please do one and give me a step by step so I can do the rest.
Data Table 1: Varying the Concentration of 1.0 M HCL
---- C o n c e n t r a t i o n s ----
#
drops
#
drops
# drops
Initial
Initial
Final
Final
Reaction Time (sec)
Reaction
Well
#
HCl
Water
Na2S2O3
HCl
Na2S2O3
HCl
Na2S2O3
Trial 1
Trial 2
Average
Rate (sec-1)
1
12
0
8
1M
0.3M
0.6M
0.12M
23.46
30.03
26.7
2
6
6
8
0.5M
0.3M
0.15M
0.12M
41.15
31.22
36.2
3
4
8
8
0.33M
0.3M
0.066M
0.12M
46.12
37.12
41.6
Data Table 1: Varying the Concentration of 1.0 M HCL
---- C o n c e n t r a t i o n s ----
#
drops
#
drops
# drops
Initial
Initial
Final
Final
Reaction Time (sec)
Reaction
Well
#
HCl
Water
Na2S2O3
HCl
Na2S2O3
HCl
Na2S2O3
Trial 1
Trial 2
Average
Rate (sec-1)
1
12
0
8
1M
0.3M
0.6M
0.12M
23.46
30.03
26.7
2
6
6
8
0.5M
0.3M
0.15M
0.12M
41.15
31.22
36.2
3
4
8
8
0.33M
0.3M
0.066M
0.12M
46.12
37.12
41.6
Explanation / Answer
Acording to the reaction, for HCl, the process is:
rate = (-1/2)*((final[]-initial[])/average time)
Number 2, is the estequimetrical coefitient for the reaction, so you can see both results and look at there are very similar.
Data Table 1: Varying the Concentration of 1.0 M HCL ---- C o n c e n t r a t i o n s ---- # # # drops Initial Initial Final Final Reaction Time (sec) Reaction drops drops Well HCl Water Na2S2O3 HCl (M) Na2S2O3 (M) HCl (M) Na2S2O3 (M) Trial 1 Trial 2 Average Rate (sec-1) (with HCl ) Rate (sec-1) (with Na2SO4 ) # 1 12 0 8 1 0.3 0.6 0.12 23.46 30.03 26.7 0.007490637 0.00674157 2 6 6 8 0.5 0.3 0.15 0.12 41.15 31.22 36.2 0.004834254 0.00497238 3 4 8 8 0.33 0.3 0.066 0.12 46.12 37.12 41.6 0.003173077 0.00432692Related Questions
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