The boiling points for a set of compounds in a homologous series can be qualitat

Question

The boiling points for a set of compounds in a homologous series can be qualitatively predicted using intermolecular force strengths. Using their condensed structural formulas, rank the homologous series for a set of alkanes by their boiling point.

Part A The boiling points for a set of compounds in a homologous series can be qualitatively predicted using intermolecular force strengths. Using their condensed structural formulas, rank the homologous series for a set of alkanes by their boiing point. Rank from highest to lowest boiling point. To rank items as equivalent, overlap them. CH3 CH3CH2CH2CH3 CH3CH2CH2CH2CH2CH3 CH3CH2CCH2CH3 CH3CH2CH2CH2CH2CH2CH3 CH3 Highest boiling point Lowest boiling point The correct ranking cannot be determined. resethelp ?help Submit Hints My Answers Give Up Review Part

Explanation / Answer

the two points to be kept in mind while ranking them

in case of alkanes

1) larger the compund , higher the boiling point

2) straight chain alkanes have higher boiling point than branched chain

because

a straight chainhas greater surface area which results in greater vanderwaal forces

greater vanderwaal forces means greater boiling points

so

using those two points

now rank the compuounds

the smallest compound is CH3CH2CH2CH3

so it has the least boling point

then

CH3CH2Ch2CH2Ch2CH3 is the smallest

so it comes next

now

CH3Ch2C(CH3)2CH2CH3 and CH3CH2CH2Ch2CH2Ch2CH3 both have 7 carbons

but as we discussed

straight chain carbonds have higher boiling points

so

CH3CH2CH2Ch2CH2Ch2CH3 has higher boiling point than CH3Ch2C(CH3)2CH2CH3

so

the order is given by

highest CH3CH2CH2Ch2CH2Ch2CH3 > CH3Ch2C(CH3)2CH2CH3 > CH3CH2Ch2CH2Ch2CH3 > Ch3Ch2CH2CH3 lowest

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