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A hot tub with a surface area of 25 ft^2 is filled with water to a depth of 28 i

ID: 869854 • Letter: A

Question

A hot tub with a surface area of 25 ft^2 is filled with water to a depth of 28 in. Hint: Volume is calculated as area X height(V = A X h). (2.5, 2.7, 2.8, 3.5) a. What is the volume, in liters, of water in the tub? b. What is the mass, in kilograms, of water it contains? c. How many kilojoules are needed to heat the water from 62 degree F to 105 degree F? d. If the hot-tub heater minutes, will it take 62 degree F to 105 degree F? provides 5900 kJ/min, how long, in to heat the water in the hot tub from A hot tub filled with water is heated to 105 degree F.

Explanation / Answer

Volume = Area Xheight

Height = 28inch = 2.33 ft

so volume = 25 X 2.33 ft^3 = 58.25 ft^3

1 f^3 = 28.31L

So 58.25ft^3 = 1649.45L

2. density of water = 1 kg/L

so amount of water = 1649.45 Kg

3. Intial temp = 620F = 16.67 0C

Final = 1050F = 40.56 0C

Specific heat of water = 4.186 kJ/kg-

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