1. The half life of sodium-24 is 15.0 hr. How many hours will it take for an ini
ID: 868215 • Letter: 1
Question
1. The half life of sodium-24 is 15.0 hr. How many hours will it take for an initially observed activity to decrease to 75% of its initial value? Answer is 6.22. The hydrogenation of ethylene occurs by the following equilibrium: C2H4(g) + 2H2(g) <=> 2CH4 Kp=1.64 @ 1000k Avessel is charged with a 1.00 atm sample of C2H4(g) and a 1.00 atm sample of H2(g). Estimate the pressure of methane gas after the system has reached equilibrium. Answer is 0.52 atm
3. Calculate the PH of a solution formed bu mixing 20.0 ml of 0.15 M HCl with 25.0 ml of 0.12 M NaOH. Answer is 7.00
How they get these answers 1. The half life of sodium-24 is 15.0 hr. How many hours will it take for an initially observed activity to decrease to 75% of its initial value? Answer is 6.2
2. The hydrogenation of ethylene occurs by the following equilibrium: C2H4(g) + 2H2(g) <=> 2CH4 Kp=1.64 @ 1000k Avessel is charged with a 1.00 atm sample of C2H4(g) and a 1.00 atm sample of H2(g). Estimate the pressure of methane gas after the system has reached equilibrium. Answer is 0.52 atm
3. Calculate the PH of a solution formed bu mixing 20.0 ml of 0.15 M HCl with 25.0 ml of 0.12 M NaOH. Answer is 7.00
How they get these answers Answer is 6.2
2. The hydrogenation of ethylene occurs by the following equilibrium: C2H4(g) + 2H2(g) <=> 2CH4 Kp=1.64 @ 1000k Avessel is charged with a 1.00 atm sample of C2H4(g) and a 1.00 atm sample of H2(g). Estimate the pressure of methane gas after the system has reached equilibrium. Answer is 0.52 atm
3. Calculate the PH of a solution formed bu mixing 20.0 ml of 0.15 M HCl with 25.0 ml of 0.12 M NaOH. Answer is 7.00
How they get these answers
Explanation / Answer
1.
A = Ao e-0.693t/t1/2
Ln (A/Ao) = -0.693t/t1/2
Ln(0.75) = -0.693t/t1/2 t1/2 = 15.0
-0.288 = (-0.693/15.0 ) t
-0.288 = -0.0462 t
t= 6.23
2.
C2H4(g) + 2H2(g) <=> 2CH4 Kp=1.64 at 1000K
1atm
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