b and c please show work. thank you! Butanoic acid (Ka = 1.52 Times 10-5 ) has a

Question

b and c please show work. thank you!

Butanoic acid (Ka = 1.52 Times 10-5 ) has a partition coefficient of 3.0 (favouring benzene) when distributed between water and benzene. Find the formal concentration of butanoic acid in each phase when 200 mL of 0.20 M aqueous butanoic acid is extracted 3 times with 50 mL of benzene ezch time at pH 3.00. A peak with a retention time of 125 s has a width at half-height of 5.5 s. A neighboring peak is eluted at 141 s width at half-height of 8.6 s. Find the resolution for these two components.

Explanation / Answer

Partition coefficient = 3

Volume of butanoic acid = 200 mL

Concentration =0.20 M

Number of moles of butanoic acid = Volume in L * molarity = 0.200 L * 0.20 M =0.04 mol Butanoic acid

Benzoic acid each time = 50 mL

pH = 3.00

volume of water = 200 mL

ka = 1.52 X 10-5

Solution :

We know

KD = [HAorg]/[HAaq]          

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