how do I solve this problem? Consider a 10 g sample of a sugar (Kp = 5) that is
ID: 866357 • Letter: H
Question
how do I solve this problem?
Explanation / Answer
wt. of sugar = 10g
Kp = 5
vol. of water = 20mL
Case1: single extraction when 20 mL ether is added:-
Let xg 0f sugar is extracted
Kp = [solute]0/ [solute]aq
5 = (x/20) / [(10-x)/20]
x = 5(10-x)
x = 50 - 5x
6x = 50
x = 8.3g or 83% sugar is extracted.
Case2: two extractions when 10 mL ether is added
First extraction:
5 = (X1/10) / [(10-X1)/20]
X1 = 7.14g
Second extraction:
5 = (X2/10) / [(2.86 - X2)/20]
X2 = 2.04g
Total sugar extracted = X1 + X2
= 7.14 + 2.04
= 9.18g or 91.8% sugar
As amount of sugar extracted in two successive extractions is 91.8% and in single extraction is 83%. Therefore the process of two successive extractions is more efficient as more amount of sugar is extracted.
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