PLEASE HELP!! The alcohol component of gasohol burns according to the equation a

Question

PLEASE HELP!!

The alcohol component of gasohol burns according to the equation a. What mass of alcohol is needed to produce 5.45 mol of H2O? b. How many moles of CO2 are produced along with 155 g of H2O? c. What mass of CO2 is produced from 146 g of C2H5OH? e. What mass of H2O is produced from 5.85 X 10^24 molecules of O2? 8-91 Nitrogen dioxide may form so-called acid rain by reaction with water in the air according to the equation What mass of nitric acid (HNO3 ) is produced from 18.5 kg of NO2?

Explanation / Answer

8-85)

a.

The given chemical reaction is

C2H5OH + 3O2 ----------> 2CO2 + 3H2O

From the chemical reaction, it is clear that 3 mol of water is produced from 1 mol of alcohol.

So, 5.45 mol of water is produced from =(5.45 mol H2O) x (1 mol C2H5OH / 3 mol H2O) = 1.82 mol C2H5OH

Moles of alcohol = 1.82 mol

Mass of alcohol = Moles of alcohol x Molar mass of alcohol

= 1.82 x 46.07 = 83.84 g C2H5OH

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b.

Given 155 g of water.

Moles of water = Mass / Molar mass = 155 g / 18 g/mol = 8.61 mol

The given chemical reaction is

C2H5OH + 3O2 ----------> 2CO2 + 3H2O

From the chemical reaction, it is clear that 3 mol of water is produced from 1 mol of alcohol.

So, 8.61 mol of water is produced from =(8.61 mol H2O) x (1 mol C2H5OH / 3 mol H2O) = 2.87 mol C2H5OH

Now, we know from chemical reaction that 2 mol of cO2 is produced from 1 mol of alcohol

So, 2.87 mol of alcohol produces = (2.87 mol C2H5OH) x (2 mol CO2 / 1 mol C2H5OH) = 5.74 mol CO2

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c.

Given, 146 g of alcohol

Moles of alcohol = 146 g / 46.07 g/mol = 3.17 mol

From the chemical reaction, it is clear that 1 mol of alcohol produces 2 mol of CO2

3.17 mol alcohol produces = (3.17 C2H5OH) x ( 2mol CO2 / 1 mol C2H5OH)

= 6.34 mol

Mass of CO2 = Moles of CO2 x Molar mass of CO2

= 6.34mol x 44g/mol = 278.96 g CO2

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e.

Given, 5.85 x 10^24 molecules of O2.

6.023 x 10^23 molecules of O2 make 1 mol

5.85 x 10^24 molecules of O2 make = (5.85 x 10^24) / (6.023 x 10^23) = 9.71 mol

From the chemical reaction, it is clear that 3 moles of O2 produces 3 moles of water.

So, 9.71 mol of O2 produces = (9.71 mol O2) x (3 mol H2O / 3 mol O2) = 9.71 mol H2O

Mass of water = Moles of H2O x Molar mass of H2O

= 9.71 x 18 = 174.8 g H2O

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8-91)

the given chemical reaction is

3NO2 + H2O ------------> 2HNO3 + NO

Given, 18.5 kg of NO2.

Mass of NO2 = 18500 g

Moles of NO2 = Mass / Molar mass = 18500 / 46 = 402.2 mol

From the given chemical reaction, it is clear that 3 mol of NO2 produce 2 mol HNO3

So, 402.2 mol NO2 produce = (402.2 mol NO2) x (2 mol HNO3 / 3 mol NO2) = 268.133 mol HNO3.

Mass of HNO3 = Moles of HNO3 x Molar mass of HNO3

Mass of HNO3 = 268.133 x 63 = 16892.4 g = 16.89 kg of HNO3

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