1. Bromine is produced in a series of chemical steps: i) H + + Br - + NaOCl = HO

Question

1. Bromine is produced in a series of chemical steps:

i) H+ + Br- + NaOCl = HOBr (hypobromous acid) + NaCl

ii) H+ + Br- + HOBr = Br2 + H2O

Give the net balanced reaction equation for this sequence.

2. Based on the answer to #1, and the balanced reaction equation for the reaction of acetanilide with bromine, whatwas the limiting reactant in this reaction? Use this to calculate your theoretical and percent yield.

3. If bromine were used in excess, dibromoacetanilide could be produced as a byproduct. What would be thestructure of the major dibrominated byproduct? Would the second bromination occur faster than the first, or slower?Explain why.

Explanation / Answer

1)

Add equation i) and ii) in ionic form

2H+ + 2Br- + Na+ + OCl- + H+ +OBr- = H+ OBr- Na+ + Cl- +Br2 + H2O

Cancel similar terms (spectator ions)

2H+ + 2Br- + + OCl- = + Cl- +Br2 + H2O

As you can see. there re 2H, 2Br, 1O, 1Cl

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