The iodide ion concentration in a solution may be determined by the precipitatio

Question

The iodide ion concentration in a solution may be determined by the precipitation of lead iodide. Pb2+(aq) + 2I-(aq) --> PbI2(s) A student finds that 16.76 mL of 0.7990 M lead nitrate is needed to precipitate all of the iodide ion in a 50.00-mL simple of an unknown. What is the molarity of the iodide ion in the student's unknown? M A student determines the calcium content of a solution by first precipitating it as calcium hydroxide, and then decomposing the hydroxide to calcium oxide by heating. How many grams of calcium oxide should the student obtain if her solution contains 49.0 mL of 0.479 M calcium nitrate? g A 0.4063 g sample of a pure soluble chloride compound is dissolved in water, and all of the chloride ion is precipitated as AgCl by the addition of an excess of silver nitrate. The mass of the resulting AgCl is found to be 0.9253 g. What is the mass percentage of chlorine in the original compound? %

Explanation / Answer

1.

Mass percentage of chlorine in the given compound is 55.9%

2.

Amount of CaO is 1.689 g

3.

Molarity of iodine ion is 0.53 M

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.