Does anyone know how to explain 15a? 15 - Propane gas flows into a combustion ch

Question

Does anyone know how to explain 15a? 15 - Propane gas flows into a combustion chamber at a rate 250 L/min at 2.0 atmand ambient temperature. Air is added to the chamber at 1.0 atm and the same temperature. The gases are ignited. a) To get complete combustion of the propane to carbon dioxide and water three times as much oxygen as is stoichiometric ally appropriate is required. Assuming air is 21% oxygen and 79% nitrogen, calculate the required flow rate of air? b )Under the conditions in part a, the combustion is not complete and a mixture of carbon dioxide and carbon monoxide is produced. It is determined that 94.0% of the carbon in the exhaust gas is present as carbon dioxide. The remainder is carbon monoxide. Calculate the percent composition of the exhaust gas in terms of

Explanation / Answer

for complete combution reaction is given as

C3H8+5O2------->3CO2+4H2O

5 mole O2 required for combution of 1 mole C3H8

n1V1P1/T1=n2V2P2/T2

1x250mlx2=5x V2x1

V2=100ml

100ml air contain 21ml O2

100mlO2is persent in 100x100/21ml air=476.190ml ofair

rate of flow=476.190ml/min

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