Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Jespersen, Chemistry, General Chemistry New Edition (6th) Chemistry 139 and Chem

ID: 858342 • Letter: J

Question

Jespersen, Chemistry, General Chemistry New Edition (6th) Chemistry 139 and Chemistry 6e Gradebook Assignment ent PRINTER VERSION BACK NEXT FULL SCREEN ti Reaction Rates and Temperature T The reaction, C2H5Br C2H4 HBr, was observed to have rate constants k 0.0000249 s at 650 K and k 0.000479 s 1 at 427 oC. What is the value of Ea expressed in mol 1? Round your answer to 3 significant figures. mol 1 The number of significant digits is set to 3, the tolerance is +/-2% Question Attempts: o of 1 used SAVE FOR LATER SUBMIT ANSWER Copyright 2000-2014 by John Wiley & Sons, Inc. or related companies. All rights reserved.

Explanation / Answer

by using the arrhenius equation , k = Ae-Ea/RT , where k = rate constant , T=temperature , Ea = activation energy , R=gas constant , let A be the constant for both cases.

in 1st case , T =650K , k=0.0000249 , by putting theses values in the above equation , we have the value of the only unknown Ea = -RT(lnK - lnA ) , so Ea = -5404.1(-10.6-lnA)

now in the 2nd case , k=0.000479 , T = 427+273= 700K , by putting all these values again in the arrhenius equation , the value of the only unknown Ea = -RT(lnK - lnA ) , so Ea =-5819.8(-7.644-lnA)

now we know that lnA is same for both , so , (Ea/-5404.1) +10.6 = (Ea/-5819.8) +7.644

solving the above equation , we get Ea = 223643.275 J/mol = 223.64KJ/mol

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote