I am working on a lab report that is due tomorrow, and I could use some help wit

Question

I am working on a lab report that is due tomorrow, and I could use some help with this NIE! Here's the question and all the info I have.

1. Write the Net Ionic Equation for the reaction in which Cu metal is dissolved to form Cu(II) ions.

**So this is the equation and the background information from this part of the lab.

Part A: Oxidizing Cu with Nitric Acid [HNO3(aq)]

In Part A, we use nitric acid to oxidize elemental Cu to copper(II) ions (Cu2+), as shown in Equation 1

Eq. 1) Cu(s) + 4H+(aq) + 2NO3-(aq) --> Cu2+(aq) +2NO2(g) +2H2O(l)

As the Cu is oxidized, NO3- ions are reduced to nitrogen dioxide (a.k.a. nitrogen (IV) oxide), NO2, a brown gas. Aqueous Cu2+ is blue because the ions form blue hexa-aquo-copper(II) complex ions, [Cu(H2O)6]2+.

Thanks!!

Explanation / Answer

Net ionic equation:

Cu(s) + 4H+(aq) + 2NO3-(aq) --> Cu2+(aq) +2NO2(g) +2H2O(l)

Oxidation half reaction:

Cu(s) ----> Cu+2(aq) + 2 e-

Reduction half reaction:

4H+(aq) + 2NO3-(aq) + 2e- --> 2NO2(g) + 2H2O(l)

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