Q1:how many grams of koh are needed to make 500ml of a 0.20 m solution? - 5.6 g
ID: 855781 • Letter: Q
Question
Q1:how many grams of koh are needed to make 500ml of a 0.20 m solution?
- 5.6 g
- 22.5 g
- 2.25g
- 0.0018 g
- 140 g
Q2: how much 1.0 m mg(no3)2 is needed to make 500 ml of 0.50 m mg(no3)2?
- 1000 mL
- 250 mL
-74 mL
-297 mL
-148 mL
Q3: which of the following is a strong electrolyte?
- Li2 CO3
-CrPO4
-BaSO4
- all are
- none is
Q4:which of the following is a strong electrolyte?
- M g(OH)2
- HNO2
- SO3
- all of the above
- none of the above
Q5: what type of reaction is 2k + 2h2o --> 2koh + h2?
- Acid-base
- Precipitation
- redox
-both acid- base and precipitation
- none of the above
Explanation / Answer
Q.1) 500ml of a 0.20 m solution
V = 500 mL = 0.5 L
M = n / V ,
0.2 = n / 0.5
n = 0.1 moles
mass = 0.1 * (39 + 1 + 16) = 5.6 grams
- 5.6 g
Q.2.)
500 ml of 0.50 m mg(no3)2?
V = 500 mL = 0.5 L
0.50 = n/ 0.5
n = 0.25 moles
1.0 m mg(no3)2 is needed , V = 0.25/1 = 0.25 L = 250
- 250 mL
Q. 3.)
- Li2 CO3
Q.4)
- Mg(OH)2
Q.5.)
- redox
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