Fructose 1, 6-bisphosphate (FBP) and phosphoenol pyruvate (PEP) are each synthes
ID: 85411 • Letter: F
Question
Fructose 1, 6-bisphosphate (FBP) and phosphoenol pyruvate (PEP) are each synthesized by transfer of a phosphate group from ATP to a precursor molecule; equilibrium constants (K) are indicated: Fructose 6-phosphate + ATP FBP + ADP K = 290 for FBP synthesis Pyruvate + ATP PEP + ADP K = 3.3 times 10^-6 for PEP synthesis Cellular concentrations are: [Fructose 6-phosphate] = 87 mu M, [FBP] = 22 mu M, [pyruvate] = 50 mu M, [PEP] = 20 mu M, [ATP] = 2 mM, [ADP] = 0.2 mM. Which statement is TRUE regarding the spontaneous direction of these two reactions? A1. FBP and PEP would both be consumed. A2. FBP and PEP would both be synthesized. A3. FBP would be consumed but PEP would be synthesized. A4. FBP would be synthesized but PEP would be consumed.Explanation / Answer
The answer is A2.
Both the reactions are energy investment phase, that means both use ATP.
The spontaneity of the reaction is calculated by gibbs free energy.
Free energy of one -P bond of ATP is conserved in the carboxylation reaction
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