An ideal gaseous reaction (which is a hypothetical gaseous reaction that conform

Question

An ideal gaseous reaction (which is a hypothetical gaseous reaction that conforms to the laws governing gas behavior) occurs at a constant pressure of 40.0atm and releases 59.6kJ of heat. Before the reaction, the volume of the system was 7.40L. After the reaction, the volume of the system was 2.20L.
Calculate the total internal energy change, delta U, in kJ:
An ideal gaseous reaction (which is a hypothetical gaseous reaction that conforms to the laws governing gas behavior) occurs at a constant pressure of 40.0atm and releases 59.6kJ of heat. Before the reaction, the volume of the system was 7.40L. After the reaction, the volume of the system was 2.20L.
Calculate the total internal energy change, delta U, in kJ:

Calculate the total internal energy change, delta U, in kJ:

Explanation / Answer

o you have the equation here, which is deltaU=q?P?deltaV, we should know everything we need, let's start with the w term, PdeltaV

Units-wise:
L*atm

In case you didn't know, this is a unit that easily converts to Joules! The conversion factor is 1 L*atm = 101.3 Joules (found on google), so basically we just have to convert from the w = 160 that you found to kJ and then solve out from there!

160 L*atm * (101.3 J/L*atm) * (1 kJ/1000 J) = 16.21 kJ

So now, we can just plug back into the equation and solve for how much internal energy is lost! Because the heat was lost out of the system, our q is a negative heat transferred, right?

so...

deltaU = -57.3kJ - 16.21kJ = -73.5 kJ!

And that should be it! Good luck and let me know if you need any more help!

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