1. Write the formulas for the following compounds, and indicate the oxidation st

Question

1. Write the formulas for the following compounds, and indicate the oxidation state of the group 4A element or of boron in each: a) silicon dioxie, b) germanium tetrachloride, c) sodium borohydride, d) stannous chloride, e) diborane, f) boron trichloride.

2. Write a balanced equation for each of the following reactions: a) hydroysis of PCl5, b) dehydration of phosphoric acid (also called orthophosphoric acid) to form pyrophosphoric acid, c) reaction of P4O10 with water.

3. Name the following compounds and assign oxidation states to the halogens in them: a) KClO3, b) Ca(IO3)2, c) AlCl3, d) HBrO3, e) H5IO6, f) XeF4

4. Complete and balance the following equations:

a) CaO (s) + H2O (l) -->

b) Al2O3 (s) + H+ (aq) -->

c) Na2O2 (s) + H2O (l) -->

d) N2O3 (g) + H2O (l) -->

e) KO2 (s) + H2O (l) -->

f) NO (g) + O3 (g) -->

Explanation / Answer

Silicon dioxide = SiO2 oxidation state Si = -4

B)germanium tetrachloride, GeCl4  oxidation state Ge= -4

c) sodium borohydride NaBH4  oxidation state B= -3

, d) stannous chloride SnCl2  oxidation state Sn = -2

, e) diborane, B2H6  oxidation state B = -3

f) boron trichloride. BCl3  oxidation state B = -3

2)

a)

PCl5 + H2O ? POCl3 + 2 HCl
In hot water, hydrolysis proceeds completely to ortho-phosphoric acid:

PCl5 + 4 H2O ? H3PO4 + 5 HCl "

b)

dehydration of orthophosphoric acid,to form pyrophosphoric acid

the difference between 2 H3PO4 's & 1 H4P2O7 is only 1 H2O, so your answer is:

2H3PO4 --> H4P2O7 + H2O

c)

1 P4O10 & 6 H2O ? 4 H3PO4

3)

KCO4 --Potassium chlorate

b) Ca(IO3)2 Calcium iodate

, c) AlCl3, Aluminium chloride

d) HBrO3, Bromic acid -or- Hydrogen bromate

e) H5IO6, Periodic acid ---- iodine exists in oxidation state VII.

f) XeF4 Xenon tetrafluoride

4)

CaO(s) + H2O(l) = Ca(OH)2(aq)

b) Al2O3 (s) + H+ (aq) -->

Al2O3(s) + 6 H+(aq) +3OH- = 2 Al(OH)3(aq) + 3 H2O(l)

c) Na2O2 (s) + H2O (l) -->

2 Na2O2 (s) + 2 H2O (?) ? 4 NaOH (aq) + O2 (g

d) N2O3 (g) + H2O (l) -->

H2O(l) + N2O3(g) = HNO2(aq)

e) KO2 (s) + H2O (l) -->

4 KO2(s) + 2 H2O(l) = 4 KOH(aq) + 3 O2(g)

f) NO (g) + O3 (g) -->

2 NO2 + O2 ? 2NO3

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