\"Write balanced molecular, ionic, and net ionic equations which show what happe
ID: 847214 • Letter: #
Question
"Write balanced molecular, ionic, and net ionic equations which show what happens in each of the following reactions."
calcium sulfite + oxalic acid ->
nickel(II) chloride + potassium cyanide ->
mercury(II) chloride + sodium sulfide ->
strontium nitrate + sodium phosphate ->
chromium + magnesium iodide ->
chlorine + chromium(III) bromide ->
silver fluoride + chromium(III) oxalate ->
mercury(I) nitrate + aluminum chloride ->
sulfuric acid + aluminum ->
cadmium chloride + aluminum nitrate ->
arsenic(III) iodide + hydrosulfuric acid ->
sodium + water ->
zinc acetate + sulfuric acid ->
oxalic acid + sodium hydroxide ->
magnesium bromide + iodine ->
water + zinc ->
Explanation / Answer
9)
Basic reaction:
Al + H2SO4 -> Al2(SO4)3 + H
Then I balanced:
2Al + 3H2(SO4) -> Al2(SO4)3 + 6H
Then, cancel out the aqeuous ions. You end up with:
2Al (s) + 6H+ -> 2Al3+ (aq) + 6H
Second problem:
Basic reaction:
Al + HCl -> AlCl3 + H
Then I balanced:
Al + 3HCl -> AlCl3 + 3H
Then, cancel out the aqeuous ions. You end up with:
Al (s) + 3H+ (aq) -> Al3+ (aq) + 3H
ALWAYS REMEMBER THAT IF THE COMPOUND IS AQEUOUS, YOU CAN CROSS IT OUT. IF IT'S SOLID, LEAVE IT ALONE. HOPEFULLY THAT HELPS :)
12)
When writing net ionic equations, each soluble compound dissociates into its ions. Covalent compounds such as water, do not produce ions in aqueous solution, so write their molecular formula.
2 Na(s) + 2 H2O(l) --> 2 NaOH(aq) + H2(g)
Total ionic:
2 Na(s) + 2 H2O(l) ---> 2 Na+(aq) + 2 OH-(aq) + H2(g)
Since there are no spectator ions, the net ionic equation is the same as the total ionic equation.
Net ionic:
2 Na(s) + 2 H2O(l) ---> 2 Na+(aq) + 2 OH-(aq) + H2(g)
14)
Start with the molecular equation:
H2C2O4(aq) + 2NaOH(aq) --> Na2C2O4(aq) + 2H2O(l)
Oxalic acid is a weak acid and not dissociated into ions. NaOH, on the other hand, is completely dissociated. Also sodium oxalate is completely dissociated. The spectator ion is the sodium ion, Na+.
The net ionic equation will look like this:
H2C2O4(aq) + 2OH- --> C2O4^2- + 2H2O(l)
16)
Zinc is naturally present in water. The average zinc concentration in seawater is 0.6-5 ppb. Rivers generally contain between 5 and 10 ppb zinc. Algae contain 20-700 ppm, sea fish and shells contain 3-25 ppm, oysters contain 100-900 ppm and lobsters contain 7-50 ppm. Elementary zinc does not react with water molecules. The ion does form a protective, water insoluble zinc hydroxide (Zn(OH)2) layer with dissolved hydroxide ions, according to the following reaction mechanism:
Zn2+ + 2OH- -> Zn(OH)2(s)
Zinc reacts with H+ ions, according to the following reaction mechanism:
Zn(s) + 2H+ -> Zn2+(aq) + H2(g)
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.