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There are a number of steps involved in determining the empirical formula of a c

ID: 845486 • Letter: T

Question

There are a number of steps involved in determining the empirical formula of a compound. You will need to demonstrate that you can complete all of these steps as you determine the empirical formula of a compound composed of phosphorus and chlorine that is 22.55 % P by mass. Complete your calculations based on 100 g of this compound. Enter all calculated values in 4 significant figures followed by one space and the appropriate unit. Use g for grams and mole for moles. Do not use scientific notation?

Determine the mass in grams of chlorine present in the sample

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Determine the number of moles of phosphorus in the sample. Answer
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Determine the number of moles of chlorine in the sample.
Answer____________

The moles of AnswerPCl represents the smaller mole value.
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Write the empirical formula of the compound. You will not be able to show subscript values correctly. For example, H2O would be recorded for water____________-

Explanation / Answer

step one

compound weight = 100g

contain only P(22.5%) and Cl(77.5%)   P = 22.5g = 22.5/31 =0.72mole Cl = 77.5g =77.5/35.4 = 2.2

step two

P(0.72) Cl(2.2)    = P Cl(2.2/0.72) =     PCl3 is the emperical formulae and molecular formulae

1) mass in gram of Cl =77.5g

2) number of mole of phospherous = 0.72mole

3) number of mole of Cl = 2.2 mole

4) smaller mole value = P Cl(2.2/0.72) = PCl3

5) emperical formulae = PCl3