For the reaction: 3BrO - (aq) --> BrO 3 - (aq) + 2Br - (aq) 1. For the reaction:

Question

For the reaction: 3BrO-(aq) --> BrO3-(aq) + 2Br-(aq)

1. For the reaction: 3BrO-(aq) --> BrO3-(aq) + 2Br-(aq) [BrO- ]initial is 0.69 M. 68 seconds later [BrO- ] is 0.13 M. What is the rate of change of [BrO- ] in M/s? (The brackets, [ ], indicate concentration, that is, molarity (M) or moles/liter.)

2.

Under a different set of conditions, the initial concentration of Br- is 0.00 M. 78 seconds later it is 0.39 M. What is the rate of change of Br- in M/s?

3.

Under a different set of conditions, the initial concentration of BrO3- is 0.17 M. 36 seconds later it is 0.66 M. What is the rate of change of BrO3- in M/s?

Explanation / Answer

Hi anon,

Average rate of change of anything is equal to (Final-Initial)/Time.

1. Rate of change of [BrO- ] =(0.13 - 0.69)/68 =     -8.2 x 10-3 M/s

2. Rate of change of [Br- ] =(0.39 - 0.00)/78 =        +5.0 x 10-3 M/s

3. Rate of change of [BrO3- ] =(0.66 - 0.17)/36 =    +1.3 x 10-2 M/s

In this reaction (or for any other reaction) rate of change of Reactant is negative and that of product is positive.

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