For each of the following gas phase atoms, give the ground state electron config

Question

For each of the following gas phase atoms, give the ground state electron configuration (EC), the valence electron configuration (VEC), the n and l quantum numbers for the highest occupied atomic orbital (HOAO), and the number of unpaired electrons. Use noble gas core notation.

a) thallium b) iron c) barium d) phosphorus

5. EXAM FORMAT CALCULATION (Note: calculators are not allowed for exams). Select the correct setup. If a sample of Ca(NO3)2 contains 17.3 g of oxygen, what is the mass of the sample? (Mm of Ca(NO3)2 = 164.03 g/mol).

a.(17.3)(164.03)(3)/16.00 b.(17.3)(164.03)/(16.00)(3) c. (17.3)(164.03)(6)/16.00 d.(17.3)(164.03)/(16.00)(6)

e.(17.3)(164.03)/16.00

Please explain why.

Explanation / Answer

Thalium ground state =   Xe 4f14 5d10 6s2 6p1 valence- 4f14 5d10 6s2 6p1 quntum number = n = 6 l = 1 m = -1 s= 1/2 number of unpaired electron = 1

Iron ground state= [Ar] 3d6 4s2 valence= 3d6 4s2   quntum number = n = 4 l = 0 m = 0 s= 1 number of unpaired electron = 4 Iron is special case it has 3d electron so there it will be 4 unpaired electron

Barium ground state = Xe 6s2 valence = 6s2 quntum number == n = 6 l = 0 m = 0 s= 1 number of unpaired electron = 1

Phosphorus ground state= Ne 3s2 3p3 valence = 3s2 3p3 quntum number == n = 3 l = 1 m = 0 s= 3/2 number of unpaired electron = 3

second part

17.3g Oxygen = 17.3/16 = 1.01mole oxygen

in Ca(NO3)2 has 6oxygen so 1.01 oxygen can produce 1.01 / 6 mole Ca(NO3)2 =0.16833mole

so weight = 0.16833*164

so answer is d.(17.3)(164.03)/(16.00)(6)

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.