Two elements, R and Q, combine to form two binary compounds. In the first compou

Question

Two elements, R and Q, combine to form two binary compounds. In the first compound, 14.0 g of R combines with 3.00 g of Q. In the second compound, 7.00 g of R combines with 4.50 g of Q. Show that these data are in accord with the law of multiple proportions. If the formula of the second compound is RQ, what is the formula for the first compound?
Two elements, R and Q, combine to form two binary compounds. In the first compound, 14.0 g of R combines with 3.00 g of Q. In the second compound, 7.00 g of R combines with 4.50 g of Q. Show that these data are in accord with the law of multiple proportions. If the formula of the second compound is RQ, what is the formula for the first compound?

Explanation / Answer

moles in 7.00 grams of R = moles in 4.50 g of Q (based on stoichiometry of second compound)

moles in 14.0 grams of R = moles in 9.0 g of Q [multiply top equation by 2]
moles in 3.00 grams of Q = moles in 4.67 g of R [divide top equation by 3/2]

The number of moles of Q weighs 3.0 grams, and the equivalent number of moles with respect to R weighs 9.0 grams. The number of moles of R in the first compound X weighs 14 grams; the equivalent number of moles with respect to Q weighs 4.667 grams. Either way you look at it, there is three times as much R as Q.

6 atoms of R for 2 atoms of Q, or 3 atoms of R for 1 atom of Q.

Then, the empirical formula (simplest ratio) is R3Q.

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