Using the reaction shown below, calculate the percent yield obtained by a studen

Question

Using the reaction shown below, calculate the percent yield obtained by a student when reacting 5.0g of 3-methoxysalicic acid with 3.9 mL of iodomethane in the presence of 10.3g of potassium carbonate and obtaining 4.5of a produce, 2,3-dimethoxymethy benzoate. You should determine which of the three reactants is the limiting reagent and the theoretical yield first. Using the reaction shown below, calculate the number of milliters of bromine required to react completely with 5g of 1.2 dimthoxybenzene.

Explanation / Answer

5g 3methoxy salycilic acid is 0.02974 mole

3.9*2.26 = 8.814g Iodomethane contains = 0.0621MOLE

10.3g K2CO3 contains 0.07453MOLE

so limiting agent is salycilic acid of 0.02974mole

hence 0.02974mole salycilic acid will produce 0.02974 mole 23dimethoxymethyl benzoate

so product weight = 0.02974*196.2 = 5.835g

theoretical yield = 5.835g

exp yield = 4.5g

% of yield = 4.5/5.83*100 = 77.18%

2)

5g 12dimethoxybenzene contains = 5/138.18 = 0.036

so we need 0.036mole Br2 = 159.8*0.036 g =5.751g

volume required v = m/d = 5.751/3.1 = 1.85ml

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