1)Calculate the number of moles of nitrogen dioxide, NO2, that could be prepared
ID: 844087 • Letter: 1
Question
1)Calculate the number of moles of nitrogen dioxide, NO2, that could be prepared from 62.0 mol of nitrogen oxide and 74.0 mol of oxygen.
2NO(g)+O2(g)? 2NO2(g)
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Identify the limiting reagent and the excess reagent in the reaction. What would happen to the potential yield of NO2 if the amount of NO were increased?
A) Increase B) Decrease C) No change
What if the amount of O2 were increased?
A) Increase B) Decrease C) No change
2)Calculate the wavelength (in m) of a photon capable of exciting an electron in Li^2+ from the state n= 2 to the state n=4
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3) Determine the potential (V) by which a proton must be accelerated so as to assume a particle wavelength of 0.0121 nm.
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4) Calculate the lattice energy of CaF2 given the information below (in kJ/mol):
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5) In an effort to purify the output from a catalytic chemical reaction, C-Cl bonds are to be broken in a gaseous compound by means of LASER radiation. Determine the longest wavelength of radiation still capable of breaking the C-Cl bond.
[Given: BEC-C = 334 kJ/mol; BECl-Cl = 243 kJ/mol]
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6)
Determine the activation energy (EA, in kJ/mol) of a reaction for which the rate triples upon a temperature increase from 39oC to 50oC.
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7) 7 volts is applied across a 1 meter length of silver filament. The filament diameter is 48 microns and the resistivity of silver is 1.59 x 10^-8 ohm-m. Calculate the current that will flow through the filament. Express your answer in amps.
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8) The charge carrier density of GaAs at 26oC is 2.25x106 cm-3. What is the charge carrier density (in cm-3) at 176oC? The bandgap of GaAs is 1.42 eV.
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Ca(g)?Ca(s) ?H=?178kJ/mol Ca(g)?Ca+(g)+e? ?H=589.8kJ/mol F(g)+e??F?(g) ?H=?328.2kJ/mol Ca2++e??Ca+(g) ?H=?1145.4kJ/mol F2(g)?2F(g) ?H=139.0kJ/mol Ca(s)+F2(g)?CaF2(s) ?H=?1219.6kJ/molExplanation / Answer
1) 31mole
limiting agent is NO
potential yield increases with increase of NO
potential yield has no change with increase of O2 because limiting agent is NO
2) wavelength ?E = 2.178 X 10-18 J[1/n2i
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