1. How much of 5.0 M NaOH is needed to make 800 mL of 0.1 M NaOH? 2. A student t

Q: 1. How much of 5.0 M NaOH is needed to make 800 mL of 0.1 M NaOH? 2. A student t

1) we use M1V1 = M2V2 formula , 5 x V1 = 0.1 x 800 V1 = vol = 16 ml 2) at equivalence point or end point NaOH moles = HCl moles ( Moles = MV where V in liters) hence 0.0943 x ( 24.5/1000) = Mx 10/1000 M = 0.231 is conc of Hcl 3) In that case we used more NaOH for titration , hence by equation Molarity of HCl calculated would be higher

ID: 841453 • Letter: 1

Question

1. How much of 5.0 M NaOH is needed to make 800 mL of 0.1 M NaOH?

2. A student titrated 10.00 mL HCL with standard NaOH in a 125 mL flask. The amount of NaOH needed was 24.50 mL. Calculate the molarity of the HCl solution if the concentration of the standarized NaOH is 0.09430 M. (The blank titration needed 0.10 mL of NaOH.)

3. Many drops of NaOH adhered to the uncleaned spots of a buret after the NaOH was deleivered in a titration of NaOH with HCl. How will this affect the molarity of HCl?

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Explanation / Answer

1) we use M1V1 = M2V2 formula , 5 x V1 = 0.1 x 800

V1 = vol = 16 ml

2) at equivalence point or end point NaOH moles = HCl moles ( Moles = MV where V in liters)

hence 0.0943 x ( 24.5/1000) = Mx 10/1000

M = 0.231 is conc of Hcl

3) In that case we used more NaOH for titration , hence by equation Molarity of HCl calculated would be higher

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1. How much of 5.0 M NaOH is needed to make 800 mL of 0.1 M NaOH? 2. A student t

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