What is the definition of the Molar Enthalpy of Reaction? Question 1 options: Th
ID: 839584 • Letter: W
Question
What is the definition of the Molar Enthalpy of Reaction?
Question 1 options:
The amount of heat in Joules require to evaporate 1 mole of reactant
The amount of heat in kJ released (exothermic) or gained (endothermic) per mole of product
The amount of energy released from gaseous expansion during a reaction.
Question 2
According to the rules of Hess' Law, which of the following reactions needed to be reversed to solve for the net molecular equation of the reaction between Hydrochloric Acid, Ammonium Hydroxide, and Sodium Acetate
Net Molecular Equation:
HCl(aq) + NH4OH(aq) + NaCH3COOH(aq) ? NaCl(aq) + H2O(l) + NH4CH3COOH(aq)
Question 2 option
A. CH3COOH(aq) + NaOH(aq) ? NaCH3COO(aq) + H2O(l)
B.
HCl(aq) + NaOH(aq) ? NaCl(aq) + H2O(l)
CH3OOH(aq) + NH4F (aq) ? NH4CH3COO(aq) + H2O(l) + F-(aq)
Question 3
What is the Molar Enthalpy of Neutralization (?Hn) in kJ/mol if 5.00 moles of HCl(aq) (acid) neutralized 5.00 moles of NaOH(aq) (base) and released 16478 J of heat?
*Make sure you report your answer using the correct sign!
Question 4
Calculate the Molar Enthalpy of Neutralization (?Hn) in kJ/mol of the exothermic reaction between a monoprotic acid and a monoprotic base, given the following information:
A.The amount of heat in Joules require to evaporate 1 mole of reactant
B.The amount of heat in kJ released (exothermic) or gained (endothermic) per mole of product
C.The amount of energy released from gaseous expansion during a reaction.
Explanation / Answer
1)
B.
The amount of heat in kJ released (exothermic) or gained (endothermic) per mole of product
2)
A.
CH3COOH(aq) + NaOH(aq) ? NaCH3COO(aq) + H2O(l)
3)
Hn=16478/5=3295.6 J
4)
5)
H=mcdT
H=100/1000 * 4.180 * 13.26=5.543 J
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