SOLVE FOR PART B SOLVE FOR PART B Acetylene, C2H2, can be converted to ethane, C

Question

SOLVE FOR PART B

SOLVE FOR PART B

Acetylene, C2H2, can be converted to ethane, C2H6, by a process known as hydrogenation. The reaction is Given the following data at standard conditions (all pressures equal to 1 atm and the common reference temperature 298 K). what is the value of Kp for this reaction? Express your answer using two significant figures. At 25 degree C the reaction from Part A has a composition as shown in the table below. What is the free energy change, delta G, in kilojoules for the reaction under these conditions? Express your answer numerically in kilojoules.

Explanation / Answer

C2H2 + 2H2 -----> C2H6

Kp = pC2H6 / pC2H2 x (pH2)^2

so

Kp = 4.25 x 10-2 / 3.55 x ( 4.25)^2

Kp = 6.628 x 10-4

we know that

dG = dGo + RT ln Kp

dG = dGo + 8.314 x 298 x ln 6.628 x 10-4

dG = -242.09 - 18.14 kJ

dG = -260.22 kJ

so dG value is -260.22 kJ

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