when the oxide of generic medal M is heated at 298k only negligible amount of M

ID: 837835 • Letter: W

Question

when the oxide of generic medal M is heated at 298k only negligible amount of M is produced.

mo2(s) <---> m(s) + o2(g) delta g = 289.8 kj / mol

when this reaction is coupled to this conversion of graphite to carbon dioxideit becomed spontaneous

what is the chemical equation of this coupled process? show that the reaction is equilibrium iclude physical states and represent graphite as c(s)

o2(s) + c(s) ---> m(s) + co2 (g)

what is the thermaldynamic equilibrium constant for the coupled reaction

(1) MO2(s) <=> M(s) + O2(g), Delta G1 = 289.8 kJ/mol

(2) C(s) + O2(g) <=> CO2(g), Delta G2 = -394.4 kJ/mol

Add equation (1) + (2):

MO2(s) + C(s) + O2(g) <=> M(s) + O2(g) + CO2(g)

Cancel common terms to get coupled reaction:

MO2(s) + C(s) <=> M(s) + CO2(g)

Delta Go = Delta G1 + Delta G2

= 289.8 + (-394.4)

= -104.6 kJ/mol = -104600 J/mol

Temperature T = 298 K

Molar gas constant R = 8.314 J/mol.K

Equilibrium constant K = exp(-Delta Go/RT)

= exp(104600/(8.314 x 298))

= 2.16 x 10^(18) = 2.16 x 1018

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