Help me solve part C The forensic technician at a crime scene has just prepared
ID: 837553 • Letter: H
Question
Help me solve part C
The forensic technician at a crime scene has just prepared a luminol stock solution by adding 10.0g of luminol into a total volume of 75.0 mL of H2 O. What is the molarity of the stock solution of luminol? Express your answer with the appropriate units. Before investigating the scene, the technician must dilute the luminol solution to a concentration of 2.00 Times 10-2 M. The diluted solution is then placed in a spray bottle for application on the desired surfaces. How many moles of luminol are present in 2.00 L of the diluted spray? Express your answer with the appropriate units. What volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B)? Express your answer with the appropriate units.Explanation / Answer
In Part A, Molarity is known which is equal to 0.753M
In Part B, Number of mols is known which is equal to 4x10-2 mols
Objective: To find the volume of A that will contain 4x10-2 mols.
0.753 Molarity means, 0.753 mols of luminol are there in 1L of solution.
Therefore, by applying unitary method 4x10-2 mols of luminol will require-:
V = (1/0.753)x (4x10-2 ) = 0.05312 L of soultion = 53.12 ml of solution
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