I\'d like the answer but also the process to arrive at it because I\'m not getti

Question

I'd like the answer but also the process to arrive at it because I'm not getting this very well (sorry it won't copy the symbols properly).

Half-life equation for first-order reactions: it t_1/2 = 0.693 over it k where t _1/2 is the half-life in seconds (s), and k is the rate constant in inverse seconds s^-1.

Part A What is the half-life of a first-order reaction with a rate constant of 4.00*10^-4 ~s^{-1}? Express your answer with the appropriate units.

Part B

What is the rate constant of a first-order reaction that takes 244 seconds for the reactant concentration to drop to half of its initial value?

Express your answer with the appropriate units.

Part C

A certain first-order reaction has a rate constant of 8.80

Explanation / Answer

A. t1/2 = 0.693/k = 1732.5 sec = 28.875 min

B. k = 0.693/244 s-1 = 2.84X10^-3 sec-1

C. time = 3Xt1/2 = 3X 0.693/k = 236.25 sec

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