A cell is set up with copper and lead electrodes in contact with CuSO4 (aq,1.0 M

Question

A cell is set up with copper and lead electrodes in contact with CuSO4 (aq,1.0 M) and Pb (NO3)2 (aq, 1.0 M), respectively, at 25°C. The standard cell potential is 0.47 V for the reaction: Cu2+ + Pb --> Cu + Pb2+

If solid sodium sulfite is added to the CuSO4 solution, a precipate of CuSO3 will form.

A. Describe how the concentrations of each copper(II) ion and lead(II) ion would change. Assume no change in the volume of solution after adding sodium sulfate.

B. Using Nernst equation, predict how the cell potential will change.

Explanation / Answer

a. due to addition of sodium sulfite and precipitation of Cu2+ ion conc. of Cu2+ will decrease due to which the reaction will proceed in backward direction and decrease the conc. of Pb2+

b. using nernst equation standard cell potential=-0.59/2*ln([Pb2+]/[Cu2+])

thus it will decrease

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