Exercise 17.70 Use data from Appendix IIB to calculate the equilibrium constants
ID: 833273 • Letter: E
Question
Exercise 17.70
Use data from Appendix IIB to calculate the equilibrium constants at 25 ?C for each of the following reactions..
Part A
N2(g)+3H2(g)?2NH3(g)
Express your answer using two significant figures.
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Part B
Br2(g)+Cl2(g)?2BrCl(g)
?G?f for BrCl(g) is -1.0 kJ/mol
Express your answer using two significant figures.
PROBLEM #2
Relationship between free energy and the equilibrium constant
The standard free energy change, ?G?, and the equilibrium constant K for a reaction can be related by the following equation:
?G?=?RTlnK
where T is the Kelvin temperature and R is equal to 8.314 J/(mol?K).
Part B
Calculate the equilibrium constant for the following reaction at room temperature, 25 ?C:
N2(g)+O2(g)?2NO(g)
Express your answer numerically to three significant figures.
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K =Explanation / Answer
N2(g)+3H2(g)?2NH3(g)
Express your answer using two significant figures.
K =
First find delta G by doing products - reactants
=
delta G = 2* (16.4) – 3(0)
delta G = -32.8 kJ/mol
or = -32800 J/ mole
delta G = -RT lnK
lnK = - delta G /RT
K= e^ - (-32800) /8.3145 *298
=e ^13.24
K = e^(16.48) = 5.62x10^5
Part B
Br2(g)+Cl2(g)?2BrCl(g)
?G?f for BrCl(g) is -1.0 kJ/mol
First find delta G by doing products - reactants
=
delta G = 2* (-1) – (0) – 3.14
delta G = -5.14 kJ/mol
or = -5140 J/ mole
delta G = -RT lnK
lnK = - delta G /RT
K= e^ - (-5140) /8.3145 *298
=e ^2.075
K = e^(2.075) = 7.96
K =
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