For the following reaction, K c = 255 at 1000 K. CO( g )+Cl2( g )?COCl2( g ) A r

Question

For the following reaction, Kc = 255 at 1000 K.
CO(g)+Cl2(g)?COCl2(g)
A reaction mixture initially contains a COconcentration of 0.1490 M and a Cl2concentration of 0.178 M at 1000 K.

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Part A

What is the equilibrium concentration of CO at 1000 K?

[CO] = ?

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Part B

What is the equilibrium concentration of Cl2 at 1000 K?

[Cl2] =?

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Part C

What is the equilibrium concentration of COCl2 at 1000 K?

[Cl2] =?

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Part C

What is the equilibrium concentration of COCl2 at 1000 K?

Explanation / Answer

For the reaction:

                CO (g)   +             Cl2(g)     ?            COCl2(g)

initially: 0.1490                   0.178                     0

Finally: 0.1490-x               0.178-x                 x

Kc=255

thus,

x/[(0.1490-x)(0.178-x)]=255

x=255x2 -83.385x+ 6.76311

Solving:

x=0.1362

So,

[CO]=0.1490-0.1362=0.128 M

[Cl2]=0.178-0.1362=0.0418M

[COCl2]=0.1362M

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