Haemophilia A in humans is a rare, recessive sex-linked trait. In a given popula

Question

Haemophilia A in humans is a rare, recessive sex-linked trait. In a given population in Hardy- Weinberg equilibrium, 0.06% of males have this phenotype. a. Assume there are only two alleles for the gene in this particular population. What are the allele frequencies for the haemophilia and the normal factor VIII alleles in this population? b) What percent of females would be expected to express haemophilia? C) What proportion of the females would you expect to be carriers for haemophilia? D) The observed frequency of women affected with haemophilia is actually higher than expected. Propose a genetic explanation for this. Show the working out please

*SOMEONE WHO KNOWS WHAT THEY ARE TALKING ABOUT PLEASE*

Explanation / Answer

Answer

A). Males will have only one chromosome so that the frequency of hemophilia male is equal to hemophilic allele frequency.

Hemophilic allele frequency (q)= 0.06

Normal allele frequency (p)= 0.94

B). Hemophilic female frequency (p^2)= 0.94*0.94= 0.88

C). Carrier female frequency (2pq) = 2*0.94*0.6= 0.11

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