Analyze and solve this partially completed galvanic cell puzzle. There are 4 ele
ID: 828452 • Letter: A
Question
Analyze and solve this partially completed galvanic cell puzzle. There are 4 electrodes each identified by a letter of the alphabet, A through D. The values in the partially completed grid are measured cell potentials for a cell consisting of electrode #1 and electrode #2. You may assume that each galvanic cell was properly constructed with the appropriate metals and solutions and that all the measured values in the grid are accurate.
electrode #1 ?
C
B
D
A
electrode #2 ?
Ecell(volts)
Ecell(volts)
Ecell(volts)
Ecell(volts)
C
0
0.91
0.62
0.01
B
0.91
0
1.53
0.90
D
0.62
1.53
0
0 volts
0.01 volts
0.28 volts
0.61 volts
0.63 volts
0.89 volts
0.90 volts
0.91 volts
0.92 volts
1.52 volts
1.54 volts
1.81 volts
2.43 volts
electrode #1 ?
C
B
D
A
electrode #2 ?
Ecell(volts)
Ecell(volts)
Ecell(volts)
Ecell(volts)
C
0
0.91
0.62
0.01
B
0.91
0
1.53
0.90
D
0.62
1.53
0
Explanation / Answer
After trying logically, we get below sequence
D-B = 1.53
D-C = 0.62
C-B = 0.91
A-B = 0.90
C-A = 0.01
D>C>A>B
We need to find D-A = D-C+C-A = 0.62+0.01 = 0.63
Cheers
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