Zn/Cu battery made DC measurement gave 1.014V and reversed -1.011V a) Using stan

Question

Zn/Cu battery made DC measurement gave 1.014V and reversed -1.011V

a) Using standard reduction potentials(lit values), calculate the standard cell potential, E(0)cell, i.e., the voltage when [Zn2+]=1.00M and [Cu2+]=1.00M

b)Using the Nernst equation, calculate the value of E cell when [Zn2+]=2.00M and [Cu2+]=1.00e-4M

c) What is happening to the observed cell potential E cell, as [Zn2+] increases and [Cu2+] decreases?

d) What is happening to the observed cell potential E(0)cell, as [Zn2+] increases and [Cu2+] decreases?

e)What will be the value of Ecell when the Cu/Zn battery has "run down," i.e., reached equilibrium?

f)What will be the value of E(0)cell when the Cu/Zn battery has "run down," i.e., reached equilibrium?

g) Will the concentrations of Zn2+ (aq) and Cu2+(aq) be large or small when the battery has "run down"? Does this make sense?

Please explain all of them

Thanks!

Explanation / Answer

e) Ecell at equilbrium is zero

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