1) What is the pH of 0.164 M HNO3? A) Is the solution neutral, acidic, or basic?

ID: 824576 • Letter: 1

Question

1) What is the pH of 0.164 M HNO3?
A) Is the solution neutral, acidic, or basic?

B) What is the pOH?

2) For a solution of pH of 4.61

A) What is the [H3O+]?

B) What is the [OH-]

C) What is the pOH

3) For a solution of pOH 8.59:

A) What is the [H3O+]?

B) What is the [OH-]?

C) What is the pH?

4) In each equation, label the acids, bases, and conjugate pairs:

A) NH3+HNO3 yeilds NH4+ + NO3-

B) CH3O- + NH3 (arrows both ways) CH3OH + NH2-

C) HPO42- + HSO4- (^) H2PO4- +SO42-

D) NH4+ +CN- (^^) NH3 + HCN

Thank you

1)pH=-log[H+]=-log[0.164]=0.78 (acidic)

pOH=14-0.78=13.22

2)[H+]=[H3O+]=10^-pH=2.45*10^-5

[OH-}=10^-14/[H+]=4.07*10^-10

pOH=14-pH=14-4.61=9.39

3)[OH-]=10^-pOH=2.57*10^-9

[H+]=[H3O+]=10^-14/[OH-]=3.89*10^-6

pH=14-pOH=14-8.59=5.41

4)diggerence in pH=-log[H3O+]A-(-log[H3O+]B)=log[H3O+]B-log[H3O+]A=log[H3O+]B/[H3O+]A=log500=2.698

5A)Acid-HNO3 base=NH3 conjugate acid-NH4+ conjugate base-NO3-

5B)acid-NH3 base-CH3O- conjugate acid-CH3OH Conjugate base-CH3OH

5C)acid-HSO4- base-HPO42- Conjuagate acid-H2PO4- Conjugate base-SO42-

5D)acid-NH4+ base-CN- Conjuagate acid-HCN Conjugate base-NH3

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