%253Cp%253ECoal%252C%2520which%2520is%2520primarily%2520carbon%252C%2520can%2520

Question

%253Cp%253ECoal%252C%2520which%2520is%2520primarily%2520carbon%252C%2520can%2520be%2520converted%2520to%2520natural%250Agas%252C%2520primarily%2520CH4%252C%253C%252Fp%253E%250A%253Cp%253Eby%2520the%2520following%2520exothermic%2520reaction.%253C%252Fp%253E%250A%253Cp%253EC(s)%252B2H2(g)%253FCH4(g)%253C%252Fp%253E%250A%253Cp%253E%253Cbr%2520%252F%253E%253C%252Fp%253E%250A%253Cp%253EPart%2520A%253C%252Fp%253E%250A%253Cp%253EWhich%2520of%2520the%2520following%2520will%2520favor%2520CH4%2520at%2520equilibrium%253F%253C%252Fp%253E%250A%253Cp%253ECheck%2520all%2520that%2520apply.%253C%252Fp%253E%250A%253Cp%253E%253Cbr%2520%252F%253E%253C%252Fp%253E%250A%253Cp%253E%253Cbr%2520%252F%253E%253C%252Fp%253E%250A%253Cp%253Eadding%2520more%2520H2%2520to%2520the%2520reaction%2520mixture%253C%252Fp%253E%250A%253Cp%253E%253Cstrong%253Eadding%2520neon%2520gas%2520to%2520the%2520reaction%2520mixture%253C%252Fstrong%253E%253C%252Fp%253E%250A%253Cp%253Eadding%2520more%2520C%2520to%2520the%2520reaction%2520mixture%253C%252Fp%253E%250A%253Cp%253Eraising%2520the%2520temperature%2520of%2520the%2520reaction%2520mixture%253C%252Fp%253E%250A%253Cp%253Elowering%2520the%2520volume%2520of%2520the%2520reaction%2520mixture%253C%252Fp%253E%250A%253Cp%253Eadding%2520a%2520catalyst%2520to%2520the%2520reaction%2520mixture%253C%252Fp%253E%250A%253Cp%253E%253Cbr%2520%252F%253E%253C%252Fp%253E%250A%253Cp%253E%253Cbr%2520%252F%253E%253C%252Fp%253E%250A%253Cp%253E%253Cspan%2520class%253D%2522c1%2522%253E%253Cstrong%253EI%2520know%2520the%2520answer%2520already%2520I%2520just%2520need%2520a%250Agood%2520explaination%2520on%2520how%2520to%2520know%2520why%2520adding%2520neon%2520gas%2520doesnt%2520effect%250Athe%2520equilibrium.%2520I%2520am%2520assuming%2520therefore%2520this%2520reaction%2520is%2520at%250Aconstant%2520volume%252C%2520but%2520how%2520would%2520I%2520figure%2520out%2520the%2520reaction%2520is%2520at%250Aconstant%2520volume%2520or%2520pressure%253F%253C%252Fstrong%253E%253C%252Fspan%253E%253Cbr%2520%252F%253E%253C%252Fp%253E%250A

Explanation / Answer

adding more H2 to the reaction mixture

adding more C to the reaction mixture

lowering the volume of the reaction mixture

note: adding of inert gas at constant pressure always faour the equlibrium shifts in decreasing the less no.of gaseous moles.

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