The first completely synthetic organic polymer was \"bakelite\" named for its in

Question

The first completely synthetic organic polymer was "bakelite" named for its inventor Leo Baekeland, a Belgian chemistry professor. Bakelite is a hard plastic used as an insulator for power plugs, distributor caps in automobiles, switches and circuit breakers, and the black handles on pots and pans. It is created by the reaction of Phenol (MM= 64.1) and formaldehyde (MM= 30).

C6h5oh + 3 Ch2o ----------> "Bakelite"

If 24.0 grams of phenol are combined with 18 grams of formaldehyde, how many grams of the reagent in excess will remain unreacted when the limiting reagent has been completely used up?

The answer is 5.2g of C6h50h Phenol. Show all steps Thanks The first completely synthetic organic polymer was "bakelite" named for its inventor Leo Baekeland, a Belgian chemistry professor. Bakelite is a hard plastic used as an insulator for power plugs, distributor caps in automobiles, switches and circuit breakers, and the black handles on pots and pans. It is created by the reaction of Phenol (MM= 64.1) and formaldehyde (MM= 30).

C6h5oh + 3 Ch2o ----------> "Bakelite"

If 24.0 grams of phenol are combined with 18 grams of formaldehyde, how many grams of the reagent in excess will remain unreacted when the limiting reagent has been completely used up?

The answer is 5.2g of C6h50h Phenol. Show all steps Thanks

Explanation / Answer

First of all, the molecular mass of phenol you have given is 94 g/mol, not 64.1, so you have 24g / 94g/mol = 0.255 mole.

You have 18g /30g/mol of formaldehyde = 0.6 mole.

But since you need 3 moles of formaldehyde per one mole of phenol, you would need 3 x 0.255 to completely react the phenol = 0.765 mole.

That means you have 0.765 - 0.6 = 0.165 mole of unreacted phenol.

So answer I get is 0.165 mol x 94 g/mole = 15.51 g of unreacted phenol, which is not the same answer that you have.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.