Which of the following represents the integrated rate law for a zero-order react

ID: 819851 • Letter: W

Question

Which of the following represents the integrated rate law for a zero-order reaction? [A]t - [A]o = - kt k = Ae(-Ea/RT) What data should be plotted to show that experimental concentration data fits a first-order reaction? 1/[reactant] vs. time [reactant] vs. time ln[reactant] vs. time ln(k) vs. 1/T ln(k) vs. Ea Which of the following statements is FALSE? The half life of a zero order reaction is dependent on concentration. The half life of a second order reaction is not dependent on concentration. The rate of second order reactions is dependent on concentration. The rate of a first order reaction is dependent on concentraion. None of the statements are FALSE. The half life for the decay of radium is 1620 years.  What is the rate constant for this first-order process? 4.28


           [A]t - [A]o = - kt
           k = Ae(-Ea/RT)

Question 2

              What data should be plotted to show that experimental concentration data fits a first-order reaction?
           1/[reactant] vs. time
           [reactant] vs. time
           ln[reactant] vs. time
           ln(k) vs. 1/T
           ln(k) vs. Ea

Question 3

              Which of the following statements is FALSE?
           The half life of a zero order reaction is dependent on concentration.
           The half life of a second order reaction is not dependent on concentration.
           The rate of second order reactions is dependent on concentration.
           The rate of a first order reaction is dependent on concentraion.
           None of the statements are FALSE.

Question 4

The half life for the decay of radium is 1620 years. What is the rate constant for this first-order process?
4.28 Which of the following represents the integrated rate law for a zero-order reaction?

Explanation / Answer

1) At = A0 - Kt

2) ln [Reactant] vs time

3) The half life of a second order is not dependent on conc.

4) 4.28 x 10^-4 yr-1 (0.693 / K)

5) At = Ao exp (-Kt)

=> At = 10.9 x exp (-0.76 x 9.6) = 7.4 x 10^-3 M

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