A solution is made by dissolving 0.687 mol of nonelectrolyte solute in 797 g of

Question

          A solution is made by dissolving 0.687 mol of nonelectrolyte solute in 797 g of benzene. Calculate the freezing point and boiling point of the solution. Constants may be found here.

Tf=?
Tb=?
          A solution is made by dissolving 0.687 mol of nonelectrolyte solute in 797 g of benzene. Calculate the freezing point and boiling point of the solution. Constants may be found here.

Tf=?
Tb=?
     A solution is made by dissolving 0.687 mol of nonelectrolyte solute in 797 g of benzene. Calculate the freezing point and boiling point of the solution. Constants may be found here.

Tf=?
Tb=?
A solution is made by dissolving 0.687 mol of nonelectrolyte solute in 797 g of benzene. Calculate the freezing point and boiling point of the solution. Constants may be found here.

Tf=?
Tb=?

Explanation / Answer

molality = 0.687 mol / 0.797 kg = 0.86198 m (mol/kg)
0.86198 x 5.12 = 4.413 f.p. depression
0.86198 x 2.53 = 2.18 b.p. elevation
f.p. = 5.5 -4.413 = 1.087 deg C

b.p. = 80.1 + 2.18 = 82.28 deg C (82.3 deg C)

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