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Question

%3Cp%3E%3Cimg%20class%3D%22user-upload%22%26nbsp%3Bsrc%3D%22http%3A%2F%2Fmedia.cheggcdn.com%2Fmedia%252Fcdb%252Fcdb4efa7-61eb-4b3a-99ac-678c4f972c6c%252FphpHGFgG1.png%22%26nbsp%3Bheight%3D%22118%22%26nbsp%3Bwidth%3D%22541%22%26nbsp%3Bdata-mce-src%3D%22http%3A%2F%2Fmedia.cheggcdn.com%2Fmedia%252Fcdb%252Fcdb4efa7-61eb-4b3a-99ac-678c4f972c6c%252FphpHGFgG1.png%22%3E%3C%2Fp%3E%3Cp%3EPleas%26nbsp%3Bhelp%26nbsp%3Bthis%26nbsp%3Bis%26nbsp%3Bdue%26nbsp%3Bin%26nbsp%3Ba%26nbsp%3Bhalf%26nbsp%3Bhour%26nbsp%3Band%26nbsp%3BI%26nbsp%3Bcant%26nbsp%3Bget%26nbsp%3Bit%26nbsp%3Bright.%3C%2Fp%3E

Explanation / Answer

specific volume=4.9/2.5=1.96 ft^3/lbm

using the steamtable for superheated steam and for a pressure of 90 psi and using the specific volume we get

specific enthalpy=290.833 Btu/lb

==> enthalpy=2.5*290.833=727.08Btu

specific internal energy=456 Btu/lb

==> internal enegry ,U=2.5*456=1140 Btu

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