1 Marks: 1 Initial rate of reaction data is given in the next question for the f

Question

1 Marks: 1 Initial rate of reaction data is given in the next question for the following reaction:

2A + B ? C +D

The rate of reaction = k[A]x[B]y. What are x and y, that is, what is the order of reaction with respect to A and B? Choose at least one answer. a. x =0 b. x = 0.5 c. x = 1 d. x = 2 e. y = 0 f. y = 0.5 g. y = 1 h. y = 2 1 Marks: 1 Marks: 1 Initial rate of reaction data is given in the next question for the following reaction:

2A + B ? C +D

The rate of reaction = k[A]x[B]y. What are x and y, that is, what is the order of reaction with respect to A and B? Choose at least one answer. a. x =0 b. x = 0.5 c. x = 1 d. x = 2 e. y = 0 f. y = 0.5 g. y = 1 h. y = 2 Initial rate of reaction data is given in the next question for the following reaction:

2A + B ? C +D

The rate of reaction = k[A]x[B]y. What are x and y, that is, what is the order of reaction with respect to A and B? Choose at least one answer. a. x =0 b. x = 0.5 c. x = 1 d. x = 2 e. y = 0 f. y = 0.5 g. y = 1 h. y = 2 Choose at least one answer. Question2 Marks: 1
Determine the rate constant from the concentration-time dependence (The units for the initial rate of reaction are Ms-1):

[A] [B] Init. Rate 0.020 0.15 0.055 0.035 0.15 0.096 0.050 0.35 0.75
Answer: Question2 Marks: 1 Marks: 1
Determine the rate constant from the concentration-time dependence (The units for the initial rate of reaction are Ms-1):

[A] [B] Init. Rate 0.020 0.15 0.055 0.035 0.15 0.096 0.050 0.35 0.75
Answer:
Determine the rate constant from the concentration-time dependence (The units for the initial rate of reaction are Ms-1):

[A] [B] Init. Rate 0.020 0.15 0.055 0.035 0.15 0.096 0.050 0.35 0.75
Answer: Answer: Question3 Marks: 1
Consider the second-order decomposition of nitroysl chloride:
2NOCl(g) ? 2NO(g) + Cl2(g)
At 450 K the rate constant is 15.4 atm-1s-1. How much time (in s) is needed for NOCl originally at a partial pressure of 40 torr to decay to 13.9 torr? Answer: Question3 Marks: 1 Marks: 1
Consider the second-order decomposition of nitroysl chloride:
2NOCl(g) ? 2NO(g) + Cl2(g)
At 450 K the rate constant is 15.4 atm-1s-1. How much time (in s) is needed for NOCl originally at a partial pressure of 40 torr to decay to 13.9 torr? Answer:
Consider the second-order decomposition of nitroysl chloride:
2NOCl(g) ? 2NO(g) + Cl2(g)
At 450 K the rate constant is 15.4 atm-1s-1. How much time (in s) is needed for NOCl originally at a partial pressure of 40 torr to decay to 13.9 torr? Answer: Answer: Question4 Marks: 1
How much time (in s) is needed for NOCl originally at a concentration of 0.0173 M to decay to 0.0031 M? Answer: Question4 Marks: 1 Marks: 1
How much time (in s) is needed for NOCl originally at a concentration of 0.0173 M to decay to 0.0031 M? Answer:
How much time (in s) is needed for NOCl originally at a concentration of 0.0173 M to decay to 0.0031 M? Answer: Answer: Question5 Marks: 1
The decomposition of formic acid (see below) is measured at several temperatures.

HCOOH(g) ? CO2(g) +H2(g)

The temperature dependence of the first-order rate constant is:

T(K) . . . . k(s-1)

800 ....0.00027 825 ....0.00049 850 ....0.00086 875 ....0.00143 900 ....0.00234 925 ....0.00372 

Calculate the activation energy, in kJ/mol.

Use all data points and do a linear regression using calculator or Excel. Do not pick 2 data points. This is less accurate and assumes all data points are equally qood. Answer: Question5 Marks: 1 Marks: 1
The decomposition of formic acid (see below) is measured at several temperatures.

HCOOH(g) ? CO2(g) +H2(g)

The temperature dependence of the first-order rate constant is:

T(K) . . . . k(s-1)

800 ....0.00027 825 ....0.00049 850 ....0.00086 875 ....0.00143 900 ....0.00234 925 ....0.00372 

Calculate the activation energy, in kJ/mol.

Use all data points and do a linear regression using calculator or Excel. Do not pick 2 data points. This is less accurate and assumes all data points are equally qood. Answer:
The decomposition of formic acid (see below) is measured at several temperatures.

HCOOH(g) ? CO2(g) +H2(g)

The temperature dependence of the first-order rate constant is:

T(K) . . . . k(s-1)

800 ....0.00027 825 ....0.00049 850 ....0.00086 875 ....0.00143 900 ....0.00234 925 ....0.00372 

Calculate the activation energy, in kJ/mol.

Use all data points and do a linear regression using calculator or Excel. Do not pick 2 data points. This is less accurate and assumes all data points are equally qood. Answer: Answer: Question6 Marks: 1
Calculate the pre-exponential term (in s -1). Answer: Question6 Marks: 1 Marks: 1
Calculate the pre-exponential term (in s -1). Answer:
Calculate the pre-exponential term (in s -1). Answer: Answer: Question7 Marks: 1
The activation energy for the isomerization ol cyclopropane to propene is 274 kJ/mol. By what factor does the rate of this reaction increase as the temperature rises from 232 to 291 oC? (The factor is the ratio of the rates.) Answer: Question7 Marks: 1 Marks: 1
The activation energy for the isomerization ol cyclopropane to propene is 274 kJ/mol. By what factor does the rate of this reaction increase as the temperature rises from 232 to 291 oC? (The factor is the ratio of the rates.) Answer:
The activation energy for the isomerization ol cyclopropane to propene is 274 kJ/mol. By what factor does the rate of this reaction increase as the temperature rises from 232 to 291 oC? (The factor is the ratio of the rates.) Answer: Answer: Question8 Marks: 1 A catalyst decreases the activation energy of a particular exothermic reaction by 20 kJ/mol, to 36 kJ/mol. Assuming that the mechanism has only one step, and that the products are 51 kJ lower in energy than the reactants, sketch approximate energy-level diagrams for the catalyzed and uncatalyzed reactions.

What is the activation energy for the uncatalyzed reverse reaction? Answer: Question8 Marks: 1 Marks: 1 A catalyst decreases the activation energy of a particular exothermic reaction by 20 kJ/mol, to 36 kJ/mol. Assuming that the mechanism has only one step, and that the products are 51 kJ lower in energy than the reactants, sketch approximate energy-level diagrams for the catalyzed and uncatalyzed reactions.

What is the activation energy for the uncatalyzed reverse reaction? Answer: A catalyst decreases the activation energy of a particular exothermic reaction by 20 kJ/mol, to 36 kJ/mol. Assuming that the mechanism has only one step, and that the products are 51 kJ lower in energy than the reactants, sketch approximate energy-level diagrams for the catalyzed and uncatalyzed reactions.

What is the activation energy for the uncatalyzed reverse reaction? Answer: Answer: Question9 Marks: 1 Marks: 1 Choose at least one answer. a. x =0 b. x = 0.5 c. x = 1 d. x = 2 e. y = 0 f. y = 0.5 g. y = 1 h. y = 2 Choose at least one answer. Question10 Marks: 1 Marks: 1 Choose at least one answer. a. x =0 b. x = 0.5 c. x = 1 d. x = 2 e. y = 0 f. y = 0.5 g. y = 1 h. y = 2 Choose at least one answer. Question Question Question Question Question
Question
a. x =0 b. x = 0.5 c. x = 1 d. x = 2 e. y = 0 f. y = 0.5 g. y = 1 h. y = 2

Explanation / Answer

Question 7

k2/k2 = e^(t2/t1)

note t1 and t2 must be in kelvin

answer is 3.72

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