Please help me, in order to get full points, put sig figs in each step and units

Question

Please help me, in order to get full points, put sig figs in each step and units thank you. = )

Given: 2CH3CHO(l) + 502(g) -> 4COz(g) + 4H20(I) Delta H = -2329.6 kJ Calculate the heat of formation of liquid CH3CHO, given the heats of formation of gaseous carbon dioxide and liquid water are -392.5 kJ and -285.8 kJ, respectively. If 10.0 g of liquid CH3CHO and 38.4 g of gaseous oxygen were combined, and the reaction shown by the above equation occurred to the maximum extent, calculate q for the reaction.

Explanation / Answer

a). for the reaction 2CH3CHO(l)+ 502(g) -----> 4CO2(g)+4H20(l)

WE HAVE

deltaH= summation of delta H of formation of product- summation of delta H of formation of reactant

so

delta Hr = 4* delta H of formation of H20 + 4*delta H of formation of CO2 - 2*delta H of formation of CH3CHO

as delta H of formation of O2(g) is 0 J

so

-2329.6*Kj= 4*(-392.5* kJ)+4*(-285.8kJ)- 2*X kJ

where X is delta H of formation of CH3CHO

so x= -191.8 kJ

b).mole of CH3CHO in 10 gm is 10/44=0.227 mol

mole of oxygen is 38.4 gm is 38.4/32=1.2 mol

so CH3CHO is limiting reagent

so wen 2 mole of CH3CHO reats q= 2329.6 kJ

so when 10/44 mole of CH3CHO reacts

q= 2329.6*10/88

q= 264.73 kJ

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