%3Cp%3E%3Cp%20style%3D%22margin%3A%26nbsp%3B0.0px%26nbsp%3B0.0px%26nbsp%3B0.0px%
ID: 818898 • Letter: #
Question
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/ Answer
a. Molarity m = W/MW*1000/V in ml
W= mass of solute (K3Fe(CN)6) = 615 mg
MW= 329.2
V= volume of solution = 500 ml
m= 0.00373633 M
B. molar concentration of K+ = 0.011208 M
c. molar concentration of Fe(CN)63- = 0.00373633 M
d.number of millimoles of K+ in 35.0 mL = 0.00016 milli moles
e. ppm of Fe(CN)63- = 0.00101 PPM
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